by Jeff Sauro | December 4, 2007 ::
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The values presented in the graphs above are approximations derived from the work of Abramowitz & Stegun. If you need precision to more that 6 decimals you are encouraged to consult multiple published tables of Z-Values.
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| March 18, 2010 | Dan wrote: |
| Only professional statisticians know how to calculate this. The rest of you damn trolls can use a graphing calculator function: invNorm(*percent in decimal form*) |
| March 3, 2010 | alexandria wrote: |
| Drew...get a life its not that cool.... |
| March 3, 2010 | Drew fickleson (Go math!) wrote: |
| I LOVE MATH!!! THIS IS THEEEE GREATEST WEBSITE EVAAAA!!! LIKE OMG!!!! I LOVE IT!!!!!!! BLESS YOU FOLKS WHO PUT THIS DANDY SITE TOGETHER!! BLESS YOU!!! |
| March 3, 2010 | alexandria wrote: |
| i would like to see the problem solved step by step |
| February 1, 2010 | JOE M. wrote: |
| If A's are given to students who scored 90% above the mean, what would be the minimum Z score of someone receiving an A? |
| January 22, 2010 | anonomous wrote: |
| need instructions or I wouldn\'t be looking for how to figure this out |
| January 22, 2010 | anonomous wrote: |
| need instructions or I wouldn\'t be looking for how to figure this out |
| January 19, 2010 | lordly nunki wrote: |
| Thanks, it's very helpful for my theses |
| October 27, 2009 | Aaron wrote: |
| If n=6 than what would the 6 Z values be and what formula do you use? Thanks |
| August 7, 2009 | Betsy wrote: |
| How can I find the z score with 26.9 as the mean and 8 as the standard deviation? |
| July 23, 2009 | anonomous wrote: |
| Would like to see the formula |
| July 7, 2009 | Phyllis Irvine wrote: |
| What is the Standard Score for a T Score of 45? Do you have a conversion chart (Standard scores with T scores equivalent)? |
| September 23, 2008 | EA wrote: |
| awesome, saved us a bunch of work at uni :D |
| September 8, 2008 | Sinead wrote: |
| Is it legitimate to transform data in z-scores, using standardised norms, and use this as the DV in a subsequent analysis (e.g. ANOVA) |
| February 21, 2008 | anonomous wrote: |
| Hi - it would be reassuring if you could also generate a pictorial representation. Otherwise, very handy tool; thanks |
| February 20, 2008 | jim gillett wrote: |
| How can I find the mean and standard deviation if all I know is the percent under the curve and two of the actual data points |
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