by Jeff Sauro | March 8, 2004 ::
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The binomial probability theorem can be used to determine the probability that a problem of probability p will occur r times during a study with n subjects. For example, if an instruction will be confusing to 50% of the user population, the probability that one subject will be confused is .5.[4]
.90 (likelihood of detection)= 1-(1-.1) n
.90 = 1-(.9) n
.90-1 = -(.9) n
- .10 = - (.9) n
.10 = .9 n
log(.10) = n(log(.90))
n = log(.10) ÷ log(.90)
Problems found = N(1-(1-L)n)
90% (Likelihood of Detection) = 1(1-(1-.1) n)
.90 = 1(1-(.9) n)
.90 = 1-.9 n
.-10 = -.9 n
log(.10) = n(log(.9))
n= log(.10) ÷ log(.90)
Likelihood of Detection (unknown) = 1(1-(1-.1) 5)
| Problem Detection Probability | Cumulative Likelihood of Detecting the Problem at Least Once (Twice) | |||||
| 0.50 | 0.75 | 0.85 | 0.90 | 0.95 | 0.99 | |
| 0.01 | 68(166) | 136(266) | 186(332) | 225(382) | 289(462) | 418(615) |
| 0.05 | 14(33) | 27(53) | 37(66) | 44(76) | 57(91) | 82(121) |
| 0.10 | 7(17) | 13(26) | 18(33) | 22(37) | 28(45) | 40(60) |
| 0.15 | 5(11) | 9(17) | 12(22) | 14(25) | 18(29) | 26(39) |
| 0.25 | 3(7) | 5(10) | 7(13) | 8(14) | 11(17) | 15(22) |
| 0.50 | 1(3) | 2(5) | 3(6) | 4(7) | 5(8) | 7(10) |
| 0.90 | 1(2) | 1(2) | 1(3) | 1(3) | 2(3) | 2(4) |


References
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